In any triangle ABC, prove that
[(b^2-c^2)/a^2]sin2A +[(c^2-a^2)/b^2]sin2B +[(a^2-b^2)/c^2]sin2C = 0
[(b^2-c^2)/a^2]sin2A +[(c^2-a^2)/b^2]sin2B +[(a^2-b^2)/c^2]sin2C = 0
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