How p^n =np^n-1 p why is this extra p added

This question was asked in Misc 19

Dipankar Choudhury

Feb. 15, 2017, 4:52 p.m.

Answers!

Davneet Singh

Feb. 15, 2017, 7:02 p.m.

Hi Dipankar,

We are differentiating with respect to x,

So,

If there was x,
d(x^2)/dx = 2 x^2-1 dx/dx = 2x

But since here it is p^n
We write

d(p^n)/dx = np^n-1 d(p)/dx

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