Answers!
X2+(√3+1)x+√3
a =.1 b =.(√3+1) c =√3
x2+√3x+x+√3
x(x+√3)+ 1(x+√3)
(x+1) (x+√3) =0
X= -1,-√3
Alpha = -1, beta =-√3
:. β+a = -b/a βa =c/a
-1-√3 = 1-√3. -1×-√3 =√3 , √3 =√3
L.h.s = r.h.s. l.s.h = r.h.s
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Answer the question...
X2+(√3+1)x+√3
a =.1 b =.(√3+1) c =√3
x2+√3x+x+√3
x(x+√3)+ 1(x+√3)
(x+1) (x+√3) =0
X= -1,-√3
Alpha = -1, beta =-√3
:. β+a = -b/a βa =c/a
-1-√3 = 1-√3. -1×-√3 =√3 , √3 =√3
L.h.s = r.h.s. l.s.h = r.h.s
Comment