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Chapter 1 Class 12 Relation and Functions | 5 questions | about 4 minutes

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Question 1 of 5
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Question 1 of 5
NCERT Exemplar
Let \(f: \mathbf{R} \rightarrow \mathbf{R}\) be defined by
$$ f(x)=\left\{\begin{array}{c} 2 x: x>3 \\ x^2: 1<x \leq 3 \\ 3 x: x \leq 1 \end{array}\right. $$
Then \(f(-1)+f(2)+f(4)\) is
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Question 2 of 5
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Let us define a relation R in \(\mathbf{R}\) as \(a \mathrm{R} b\) if \(a \geq b\). Then R is
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Question 3 of 5
NCERT Exemplar
Let \(f:[0,1] \rightarrow[0,1]\) be defined by \(f(x)=\left\{\begin{array}{c}x, \text { if } x \text { is rational } \\ 1-x, \text { if } x \text { is irrational }\end{array}\right.\)
Then \((f \circ f) x\) is
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Question 4 of 5
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Let \(\mathbf{N}\) be the set of natural numbers and the function \(f: \mathbf{N} \rightarrow \mathbf{N}\) be defined by \(f(n)=2 n+3 \forall n \in \mathbf{N}\). Then \(f\) is
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Question 5 of 5
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Let \(f: \mathbf{R}-\left\{\frac{3}{5}\right\} \rightarrow \mathbf{R}\) be defined by \(f(x)=\frac{3 x+2}{5 x-3}\). Then
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