Teachoo Quiz

Short Quiz

Chapter 5 Class 8 - Number Play (Ganita Prakash) | 5 questions | about 4 minutes

Attempt time 0:00
This question 0:00
Question 1 of 5
Advertisement
Question 1 of 5
Assertion (A): Every number divisible by both 4 and 6 is divisible by 24.
Reason (R): The least common multiple of 4 and 6 is 12.
Select an option to see the answer, or skip this question.
Question 2 of 5
Assertion (A): The sum of two numbers that are not divisible by 6 can never be divisible by 6.
Reason (R): Two non-zero remainders can add to 6; for example, remainders 1 and 5.
Select an option to see the answer, or skip this question.
Question 3 of 5
Assertion (A): The sum of a multiple of 6 and a multiple of 9 is always a multiple of 3.
Reason (R): Every such sum is a multiple of 18.
Select an option to see the answer, or skip this question.
Question 4 of 5
Assertion (A): The sum of four consecutive integers can never be odd.
Reason (R): If the first integer is \(n\), the sum is \(4n+6=2(2n+3)\).
Select an option to see the answer, or skip this question.
Question 5 of 5
Assertion (A): 288 is the smallest three-digit multiple of 9 made only from even digits.
Reason (R): 288 is divisible by 2.
Select an option to see the answer, or skip this question.
Stuck? Keep your progress moving.