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Maths Sequences and Series Class 11 Assertion and Reason Questions

Assertion Reasoning Quiz · Class 11 · Maths · CBSE

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Chapter 8 Class 11 Sequences and Series | 7 questions | about 6 minutes

Practise Sequences and Series Class 11 with Teachoo's Assertion Reasoning Quiz (Class 11 · Maths · CBSE). Practise these questions in a free interactive quiz with answer feedback.

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Question 1 of 7
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Question 1 of 7
Assertion (A): The geometric mean (G.M.) of 4 and 16 is 8.
Reason (R): The geometric mean of two positive numbers \(a\) and \(b\) is given by \(\frac{a+b}{2}\).
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Question 2 of 7
Assertion (A): A sequence can be regarded as a function whose domain is the set of natural numbers.
Reason (R): Every mathematical sequence must be expressible by an explicit algebraic formula.
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Question 3 of 7
Assertion (A): The sum of the sequence 7, 77, 777... to \(n\) terms is evaluated by directly applying the sum formula for a Geometric Progression.
Reason (R): The sequence 7, 77, 777... is not a G.P. itself, but can be rewritten as \(\frac{7}{9} [(10-1) + (10^2-1) + \dots]\) to form geometric series.
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Question 4 of 7
Assertion: The first four terms of the sequence \(a_n=3\cdot 2^{n-1}\) are \(3,6,12,24\), and they form a G.P.
Reason: The ratio of every term to its immediately preceding term is \(2\).
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Question 5 of 7
Assertion (A): If the terms of a G.P. are all multiplied by 3, the resulting sequence is also a G.P.
Reason (R): The common ratio of the new sequence becomes 3 times the original common ratio.
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Question 6 of 7
Assertion (A): Three geometric means between 1 and 256 are 4, 16, and 64.
Reason (R): If \(n\) geometric means are inserted between \(a\) and \(b\), the common ratio is given by \(r = (\frac{b}{a})^{\frac{1}{n+1}}\).
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Question 7 of 7
Assertion (A): If the A.M. and G.M. of two positive numbers are 10 and 8 respectively, the numbers are 16 and 4.
Reason (R): The two numbers are the roots of the quadratic equation \(x^2 - 2(A.M.)x + (G.M.)^2 = 0\).
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