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Maths Linear Inequalities Class 11 Assertion and Reason Questions

Assertion Reasoning Quiz · Class 11 · Maths · CBSE

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Chapter 5 Class 11 Linear Inequalities | 6 questions | about 5 minutes

Practise Linear Inequalities Class 11 with Teachoo's Assertion Reasoning Quiz (Class 11 · Maths · CBSE). Practise these questions in a free interactive quiz with answer feedback.

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Question 1 of 6
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Question 1 of 6
Assertion (A): The solution set for the system of inequalities \( x > 5 \) and \( x < -2 \) is an empty set (\( \emptyset \)).
Reason (R): There is no real number that is simultaneously greater than 5 and less than -2.
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Question 2 of 6
Assertion (A): If \( -3x < 12 \), then the solution for real \( x \) is \( x > -4 \).
Reason (R): Both sides of an inequality can be multiplied or divided by a negative number, provided the sign of inequality is reversed.
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Question 3 of 6
Assertion (A): If \( x > y \), then \( x + c > y + c \) for any real number \( c \).
Reason (R): Equal numbers can be added to (or subtracted from) both sides of an inequality without affecting the sign of the inequality.
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Question 4 of 6
Assertion (A): The graphical representation of \( 2x - 4 < 0 \) on a number line corresponds to the solution interval \( (-\infty, 2) \).
Reason (R): \( 2x - 4 < 0 \Rightarrow 2x < 4 \Rightarrow x < 2 \). Since it is a strict inequality, the boundary point 2 is excluded, and the solution covers all values strictly less than 2.
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Question 5 of 6
Assertion (A): If \( x > 2 \), then \( \frac{1}{x} > \frac{1}{2} \).
Reason (R): Taking the reciprocal of both sides of an inequality consisting of positive numbers reverses the inequality sign.
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Question 6 of 6
Assertion (A): For pairs of consecutive odd natural numbers both larger than 10 with a sum less than 40, the pair (19, 21) is a valid solution.
Reason (R): If \( x \) is the smaller odd number, \( x > 10 \) and \( x + (x+2) < 40 \Rightarrow 2x < 38 \Rightarrow x < 19 \). Thus, \( x \) can only be up to 17.
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