Teachoo Quiz

10 Question MCQ (including Assertion)

Chapter 6 Class 11 Permutations and Combinations | 10 questions | about 8 minutes

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Question 1 of 10
Question 1 of 10
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The number of different four digit numbers that can be formed with the digits 2 , 3, 4, 7 and using each digit only once is
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Question 2 of 10
Assertion (A): The number of 3-letter words that can be formed using the letters A, B, C, D (where repetition is allowed) is 64.

Reason (R): If repetition of letters is not allowed, the number of 3-letter words formed from A, B, C, D is 24.
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Question 3 of 10

Assertion: The letters of DAUGHTER can be arranged in 4320 ways if all three vowels are together.


Reason: Since all eight letters of DAUGHTER are distinct, their total number of unrestricted arrangements is \(8!\).

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Question 4 of 10

How many 3-digit even numbers can be formed from the digits 1, 2, 3, 4, 5 and 6 if repetition of digits is allowed?

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Question 5 of 10
NCERT Exemplar
Given 5 different green dyes, four different blue dyes and three different red dyes, the number of combinations of dyes which can be chosen taking at least one green and one blue dye is
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Question 6 of 10
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The number of words which can be formed out of the letters of the word ARTICLE, so that vowels occupy the even place is
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Question 7 of 10

Assertion: \(5!-3!=2!\).


Reason: Factorial notation does not distribute over subtraction; in general, \(a!-b!\neq (a-b)!\).

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Question 8 of 10
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The number of parallelograms that can be formed from a set of four parallel lines intersecting another set of three parallel lines is
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Question 9 of 10

Assertion: If \({}^{n}C_{8}={}^{n}C_{2}\), then \(n=10\) and \({}^{n}C_{2}=45\).


Reason: If \({}^{n}C_{r}={}^{n}C_{s}\) and \(r\neq s\), then \(r+s=n\).

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Question 10 of 10

Assertion: Using the digits 1, 2, 3, 4, 5 and 6 without repetition, 60 different 3-digit even numbers can be formed.


Reason: Since the digits are not repeated and their order matters, the problem involves permutations.

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