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Maths Power Play - Chapter 2 Class 8 (Ganita Prakash) Assertion and Reason Questions

Assertion Reasoning Quiz · Class 8 · Maths · CBSE

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Chapter 2 Class 8 - Power Play (Ganita Prakash) | 7 questions | about 6 minutes

Practise Power Play - Chapter 2 Class 8 (Ganita Prakash) with Teachoo's Assertion Reasoning Quiz (Class 8 · Maths · CBSE). Practise these questions in a free interactive quiz with answer feedback.

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Question 1 of 7
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Question 1 of 7
Assertion: \((-1)^{56}\) is positive.
Reason: Every power of a negative number is positive.
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Question 2 of 7
Assertion: A digits-only code of length 9 is sufficient to give a unique code to each of \(8.5\times10^9\) milk packets.
Reason: \(10^9<8.5\times10^9<10^{10}\), so at least 10 digits are required.
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Question 3 of 7
Assertion: A 4-character alphanumeric code, using capital letters and digits with repetition allowed, has \(36^4\) possible codes.
Reason: There are 40 possible symbols for each position: 26 letters and 14 digits.
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Question 4 of 7
Assertion (A): \( 6^4 \times 3^2 \) is equal to \( 2^4 \times 3^6 \).
Reason (R): The power of a product rule states that \( (m \times n)^a = m^a \times n^a \).
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Question 5 of 7
Assertion: A ladder with steps \(20\text{ cm}\) apart would require approximately \(1.922\times10^9\) steps to cover \(3{,}84{,}400\text{ km}\).
Reason: This is exponential growth because the distance is multiplied by a fixed factor at every step.
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Question 6 of 7
Assertion (A): If the human population is \( 8 \times 10^9 \) and the elephant population is \( 4 \times 10^5 \), there are 20,000 humans for every elephant.
Reason (R): Dividing the human population by the elephant population: \( (8 \times 10^9) \div (4 \times 10^5) = 2 \times 10^4 = 20,000 \).
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Question 7 of 7
Assertion (A): When a paper is folded 46 times, its thickness increases linearly.
Reason (R): Folding a paper in half doubles its thickness with every fold, which represents multiplicative or exponential growth.
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