Teachoo Quiz

10 Question MCQ (including Assertion)

Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar | 10 questions | about 8 minutes

Attempt time 0:00
This question 0:00
Question 1 of 10
Advertisement
Question 1 of 10
A triangular logo is enlarged so that every side becomes twice as long. What is the minimum number of congruent copies of the original logo that can exactly cover the enlarged logo?
Select an option to see the answer, or skip this question.
Question 2 of 10
An isosceles triangle has a base of 10 cm and an area of \( 60 \text{ cm}^2 \). What is the length of one of its equal sides?
Select an option to see the answer, or skip this question.
Question 3 of 10
Find the area of a triangle whose side lengths are \(8\text{ cm}\), \(11\text{ cm}\), and \(13\text{ cm}\).
Select an option to see the answer, or skip this question.
Question 4 of 10
Consider all rectangles having perimeter \(40\) units. Which statement is correct?
Select an option to see the answer, or skip this question.
Question 5 of 10
The ratio of the perimeters of two circles is 5:4. What is the ratio of their areas?
Select an option to see the answer, or skip this question.
Question 6 of 10
Assertion: Two parallelograms having the same pair of adjacent side lengths must have equal areas.
Reason: The area of a parallelogram is the product of a base and its corresponding perpendicular height.
Select an option to see the answer, or skip this question.
Question 7 of 10
Assertion (A):
The exact area of an equilateral triangle of side \( a \) is \( \frac{\sqrt{3}}{4}a^2 \).
Reason (R):
Heron's formula can only be used for scalene triangles and fails for equilateral triangles because all sides are identical.
Select an option to see the answer, or skip this question.
Question 8 of 10
A circular lawn has radius \(14\text{ m}\). A \(60^\circ\) sector is used as a flower bed. What area remains as grass? Use \(\pi=\dfrac{22}{7}\).
Select an option to see the answer, or skip this question.
Question 9 of 10
Assertion: In the same circle, an arc subtending \(120^\circ\) at the centre is twice as long as an arc subtending \(60^\circ\).
Reason: The length of an arc of radius \(r\) and central angle \(\theta\) is \[l=2\pi r\times\frac{\theta}{360^\circ}.\]
Select an option to see the answer, or skip this question.
Question 10 of 10
A circular pond of radius \(7\text{ m}\) lies inside a circular park of radius \(14\text{ m}\). What area of the park lies outside the pond? Use \(\pi=\dfrac{22}{7}\).
Select an option to see the answer, or skip this question.
Stuck? Keep your progress moving.