CBSE Past Year MCQ Quiz

The figure represents the variation of the electric potential V at a point in a region of space as a function of its position along the x-axis. A charged particle will experience the maximum force at :

Two points R and S are equidistant from two charges + Q and – 2Q. The work done in moving a charge – Q from point R to S is :

A particle of mass m and charge q starts from rest and moves in an electric field \(\vec{E}=E_0\hat{i}\). After travelling a distance x in the field along x-axis, the kinetic energy of the particle will be:

An electric dipole with dipole moment \(\vec{P}\) = (2·54 × \(10^{−28}\) C.m) (2·00 \(\hat{i}\) + 3·00 \(\hat{j}\) ) is placed in an electric field \(\vec{E}\) = 1000\(\frac{N}{C}\) \(\hat{i}\) . An external agent turns the dipole until its electric dipole moment is \(\vec{P}\) = (2·54 × \(10^{−28}\) C.m) (− 3·00 \(\hat{i}\) + 2·00 \(\hat{j}\) ). The work done by the agent is :