Teachoo MCQ Test

10 Question MCQ (including Assertion)

Preparing for CBSE

Chapter 6 Class 9 - Measuring Space: Perimeter and Area (Ganita Manjar | 10 questions

Timed test. Answer every question before time runs out. Correct answers and solutions appear after submission.
Time remaining 888
Question 1 of 10
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Question 1 of 10
Assertion: Two parallelograms having the same pair of adjacent side lengths must have equal areas.
Reason: The area of a parallelogram is the product of a base and its corresponding perpendicular height.
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Question 2 of 10
How does Brahmagupta's formula generalise Heron's formula for the area of a triangle with sides \( a, b, c \)?
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Question 3 of 10
Semicircles are drawn on all three sides of a right-angled triangle as diameters. Let Area(A) and Area(B) be the areas of the semicircles on the legs, and Area(C) be the area of the semicircle on the hypotenuse. Which relationship holds true?
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Question 4 of 10
If you use Heron's formula to find the area of an equilateral triangle with side \( a \), what is the resulting simplified expression?
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Question 5 of 10
Two paths connect points \( P \) and \( Q \). Path A is a single large semicircle of diameter \( D \). Path B consists of three adjacent semicircles with diameters \( d_1, d_2, d_3 \) such that \( d_1+d_2+d_3=D \). Which path is longer?
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Question 6 of 10
A triangle is enlarged so that each side becomes three times the corresponding original side. The new area is:
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Question 7 of 10
A triangle has sides of 8 cm and 11 cm, and its total perimeter is 32 cm. What is its exact area?
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Question 8 of 10
Assertion (A):
The perimeter of a quarter circle (quadrant) of radius \( r \) is exactly \( \frac{\pi r}{2} \).
Reason (R):
The boundary of a sector of a circle includes both the length of the circular arc and the two straight bounding radii.
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Question 9 of 10
The area of a right-angled triangle is 54 sq cm. One of its legs has a length of 12 cm. Find its perimeter.
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Question 10 of 10
Assertion: In the same circle, an arc subtending \(120^\circ\) at the centre is twice as long as an arc subtending \(60^\circ\).
Reason: The length of an arc of radius \(r\) and central angle \(\theta\) is \[l=2\pi r\times\frac{\theta}{360^\circ}.\]
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