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Transcript

Example 12 Simplify and write the answer in the exponential form (i) (〖12〗^4 × 〖 9〗^3 × 4)/(6^3 ×〖 8〗^2 × 27) (〖12〗^4 × 9^3 × 4)/(6^3 × 8^2 × 27) = ((2 × 2 × 3)^4 × (3 × 3)^3 × (2 × 2))/((2 × 3)^3 × 〖(2 × 2 × 2)〗^2 × (3 × 3 × 3)) = ((2^2 × 3)^4 × (3^2 )^3 × (2^2 ))/((2 × 3)^3 × 〖(2^3)〗^2 × (3^3)) = ((2^2 )^4 × (3)^4 × (3^2 )^3 × (2^2))/(2^3 × 3^3 × (2^3 )^2×〖 3〗^3 ) = (2^(2 × 4) × 3^4 × 3^(2 × 3) ×〖 2〗^2)/(2^3 × 3^3 × 2^(3 × 2) × 3^3 ) [(a × b)m = am × bm] [(am)n = am × n] = (2^8 × 3^4 × 3^6 ×〖 2〗^2)/(2^3 × 3^3 × 2^6 × 3^3 ) = ((2^8 ×〖 2〗^2 ) × (3^4 × 3^6))/((2^3 × 2^6 ) × (3^3 × 3^3)) = (2^(8 + 2) × 3^(4 + 6))/(2^(3 + 6) ×〖 3〗^(3 + 3) ) = 2^10/2^9 × 3^10/3^6 = 210 − 9 × 310 − 6 = 21 × 34 = 2 × 81 = 162 (Using am × an = am + n) (Using 𝑎^𝑚/𝑎^𝑛 = am − n)

  1. Chapter 11 Class 7 Exponents and Powers
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo