1. Chapter 7 Class 8 Comparing Quantities
  2. Serial order wise
  3. Ex 7.3
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Question 1 (a) - Ex 7.3 - Chapter 7 Class 8 Comparing Quantities

Last updated at Dec. 16, 2024 by Teachoo

 

Transcript

Question 1 1 (a) Calculate the amount and compound interest on (a) Rs 10,800 for 3 years at 12 1/2 % per annum compounded annually Given, Principal (P) = 10, 800 Time = 3 years Rate (R) = 12 1/2 per Annum compounded Annually. = 25/2 % Amount (A) = P (1+๐‘…/100)^๐‘› = 10,800 (1+(25/2)/100)^3 = 10,800 (1+25/(2 ร— 100))^3 = 10,800 (1+1/(2 ร—4))^3 = 10,800 (1+1/8)^3 = 10,800 ((8 + 1)/8)^3 = 10,800 ร— (9/8)^3 = 10,800 ร— (9 ร— 9 ร— 9 )/(8 ร— 8 ร— 8 ) = 5400 ร— (9 ร— 9 ร— 9 )/(4 ร— 8 ร— 8 ) = 2700 ร— (9 ร— 9 ร— 9 )/(2 ร— 8 ร—8 ) = 2700 ร— (81 ร— 9 )/(2 ร— 64 ) = 2700 ร— 729/(128 ) = 2700 ร— 729/(128 ) = 1968300/(128 ) = 15377.34 โˆด Amount after 3 years = Rs 15,377.34 Now, Amount = Principal + Interest 15377.34 = 10800 + Interest 15377.34 โ€“ 10800 + Interest 4577.34 = Interest โˆด Interest = Rs 4,577.34
  1. Chapter 7 Class 8 Comparing Quantities
  2. Serial order wise

    3. Ex 7.3

    Examples →
Examples →
Chapter 7 Class 8 Comparing Quantities
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo