Example 3 - Congruence of Triangles
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Example 3 - Chapter 7 Class 7 NCERT In Fig 7.13, AD = CD and AB = CB. (i) State the three pairs of equal parts in ∆ABD and ∆CBD. In ∆ABD and ∆CBD AB = CB (Given) AD = CD (Given) BD = BD (Common) Example 3 In Fig 7.13, AD = CD and AB = CB. (ii) Is ∆ABD ≅ ∆CBD? Why or why not? In ∆ABD and ∆CBD AB = CB (Given) AD = CD (Given) BD = BD (Common) ∴ ∆ABD ≅ ∆CBD (SSS Congruence Rule) Example 3 In Fig 7.13, AD = CD and AB = CB. (iii) Does BD bisect ∠ABC? Give reasons. Since ∆ABD ≅ ∆CBD By CPCT, ∠ABD = ∠CBD Hence, BD divides ∠ABC into two equal parts ∴ BD bisects ∠ABC
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo