Last updated at Dec. 16, 2024 by Teachoo
Example 1 Construct a triangle ABC, in which ∠B = 60°, ∠C = 45° and AB + BC + CA = 11 cm Given ∠B = 60°, ∠C = 45° and AB + BC + CA = 11 cm Let’s construct Δ ABC Steps of Construction : Draw a line segment XY equal to AB + AC + BC = 11 cm. Make angle equal to ∠ B = 60° from point X Let the angle be ∠ LXY. Make angle equal to ∠C = 45° from point Y Let the angle be ∠ MYX 4. Bisect angles ∠ LXY and ∠ MYX. Let these bisectors intersect at a point A . 5. Make perpendicular bisector of AX Let it intersect XY at point B 6. Make perpendicular bisector of AY Let it intersect XY at point C 7. Join AB & AC ∴ Δ ABC is the required triangle
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo