Example 5 - Chapter 13 Class 11 Statistics
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Example 5 - Chapter 15 Class 11 Statistics - NCERT Find the mean deviation about the median for the following data: xi 3 6 9 12 13 15 21 22 fi 3 4 5 2 4 5 4 3 c.f is Cumulative frequency N = 29 (odd) β΄ Median = ((π + 1)/2)^π‘βterm = ((29 + 1)/2)^π‘β term = (30/2)^π‘β term = 15th term Now, finding mean deviation about median As, 15th term lie in c.f of 21. Median = 30 β128βππ = 29 β128βππ |π₯π βM| = 148 β΄ Mean Deviation = (Ξ£ π_π |π₯_(π )β M|)/π_π = 148/29 = 5.1
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo