Ex 3.2, 9 - Chapter 3 Class 11 Trigonometric Functions
Last updated at Dec. 13, 2024 by Teachoo
Last updated at Dec. 13, 2024 by Teachoo
Ex 3.2,9 Find the value of the trigonometric function sin (β11"Ο" /3) sin ((βππ π )/π) = βsin ((11 π)/3) = βsin ("3 " π/π " Ο" ) = βsin ("4Ο β " π/π " Ο" ) = βsin ((βπ)/π " Ο" ) Rough So, 11/3 = 3 2/3 = 3 + 2/3 or 4 β 1/3 We take 4 β π/π as it is even = β ("βsin " (1/3 " Ο" )) = sin (π/π " Ο" ) = sin 60Β° = βπ/π
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