Last updated at Dec. 13, 2024 by Teachoo
Ex 3.2, 1 Find the values of other five trigonometric functions if cosβ‘π₯ = β 1/2 , x lies in third quadrant. Since x is in 3rd Quadrant sin and cos will be negative But, tan will be positive Given cos x = (β1)/2 We know that sin2 x + cos2 x = 1 sin2 x + ((β1)/2)^2 = 1 sin2 x + π/π = 1 sin2 x = 1 β 1/4 sin2 x = (4 β 1)/4 sin2x = π/π sin x = Β±β(3/4) sin x = Β± βπ/π Since x is in 3rd Quadrant And, sin x is negative in 3rd Quadrant β΄ sin x = ββπ/π Finding tan x tan x = sinβ‘π₯/cosβ‘π₯ = (ββ3/2)/((β1)/2) = (ββ3)/2 Γ 2/(β1) = βπ Finding cot x cot x = 1/tanβ‘π₯ = π/βπ Finding sec x sec x = 1/cosβ‘π₯ = 1/((β1)/2) = (β2)/1 = β2 Finding cosec x cosec x = 1/sinβ‘π₯ = 1/((ββ3)/2) = (βπ)/βπ
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo