Last updated at Dec. 13, 2024 by Teachoo
Question 2 Is it true that for any sets A and B, P (A) ∪ P (B) = P (A ∪ B)? Justify your answer. (If it is false, we take an example to prove it) Let A = {0, 1} and B = {1, 2} ∴ A ∪ B = {0, 1, 2} P(A ∪ B) = {∅, {0}, {1}, {2}, {0, 1}, {1, 2}, {0, 2}, {0, 1, 2} } ∴ P(A) ∪ P(B) ≠ P(A ∪ B) So, the given statement is False P(A) = {∅ , {0}, {1}, {0, 1}} P(B) = {∅, {1}, {2}, {1, 2}} P(A) ∪ P(B) = {∅, {0}, {1}, {0, 1}, {2}, {1, 2}}
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About the Author
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo