1. Chapter 6 Class 10 Triangles
  2. Serial order wise
  3. Ex 6.2
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Ex 6.2, 3 - Chapter 6 Class 10 Triangles

Last updated at Dec. 13, 2024 by Teachoo

Transcript

Ex 6.2,3 In figure, if LM || CB and LN || CD, prove that ๐ด๐‘€/๐ด๐ต = ๐ด๐‘/๐ด๐ท Given: LM II CB And LN II CD To prove: ๐ด๐‘€/๐ด๐ต = ๐ด๐‘/๐ด๐ท Proof: From (1) & (2) ๐ด๐‘€/๐‘€๐ต = ๐ด๐‘/๐‘๐ท ๐‘€๐ต/๐ด๐‘€ = ๐‘๐ท/๐ด๐‘ Adding 1 on both sides ๐‘€๐ต/๐ด๐‘€ + 1 = ๐‘๐ท/๐ด๐‘ + 1 (๐‘€๐ต + ๐ด๐‘€)/๐ด๐‘€ =(๐‘๐ท + ๐ด๐‘)/๐ด๐‘ ๐ด๐ต/๐ด๐‘€ =๐ด๐ท/๐ด๐‘ ๐ด๐‘€/๐ด๐ต=๐ด๐‘/๐ด๐ท Hence proved
  1. Chapter 6 Class 10 Triangles
  2. Serial order wise

    3. Ex 6.2

    Ex 6.3 →
Ex 6.3 →
Chapter 6 Class 10 Triangles
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo