1. Chapter 10 Class 7 Algebraic Expressions
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  3. Adding and Subtracting Like terms - Worksheet
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Question 3 (vii) - Adding and Subtracting Like terms - Worksheet - Chapter 10 Class 7 Algebraic Expressions

Last updated at Dec. 16, 2024 by Teachoo

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Question 3 (Method 1) Subtract: (vii) 5a2 – 7ab + 5b2 from 3ab – 2a2 – 2b2 (3ab – 2a2 – 2b2) − (5a2 – 7ab + 5b2 ) = 3ab – 2a2 – 2b2 − 5a2 + 7ab − 5b2 = −2a2 − 5a2 − 2b2 − 5b2 + 3ab + 7ab = a2 (−2 − 5) + b2 (−2 − 5) + ab (3 + 7) = a2 (−7) + b2 (−7) + ab (10) = −7a2 − 7b2 + 10ab Question 3 (Method 2) Subtract: (vii) 5a2 – 7ab + 5b2 from 3ab – 2a2 – 2b2 We need to subtract ((5a2 – 7ab + 5b2 ) from (3ab – 2a2 – 2b2) 5a2 − 7ab + 5b2 from 3ab − 2a2 − 2b2 Answer is 10ab – 7a2 – 7b2
  1. Chapter 10 Class 7 Algebraic Expressions
  2. Serial order wise

    3. Adding and Subtracting Like terms - Worksheet

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Chapter 10 Class 7 Algebraic Expressions
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo