1. Chapter 2 Class 9 Polynomials
  2. Serial order wise
  3. Remainder Theorem
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Question 1 (iv) - Remainder Theorem - Chapter 2 Class 9 Polynomials

Last updated at Dec. 16, 2024 by Teachoo

Transcript

Question 1 Find the remainder when x3 + 3x2 + 3x + 1 is divided by (iv) x + π Dividing x3 + 3x2 + 3x + 1 by x + π Step 1: Put Divisor = 0 x + π = 0 x = – π Step 2: Let p(x) = x3 + 3x2 + 3x + 1 Putting x = – π p("−" 𝜋) = ("−" 𝜋)3 + 3("−" 𝜋)2 + 3("−" 𝜋) + 1 = – 𝜋3 + 3𝜋2 – 3𝜋 + 1 Thus, remainder = p("−" 𝜋) = – 𝜋3 + 3𝜋2 – 3𝜋 + 1
  1. Chapter 2 Class 9 Polynomials
  2. Serial order wise

    3. Remainder Theorem

    Definition →
Definition →
Chapter 2 Class 9 Polynomials
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo