1. Chapter 6 Class 9 Lines and Angles
  2. Serial order wise
  3. Examples
Check sibling questions

Example 4 - Chapter 6 Class 9 Lines and Angles

Last updated at Dec. 13, 2024 by Teachoo

Transcript

Example 4 In figure, if PQ || RS, MXQ = 135 and MYR = 40 , find XMY. Let AB || PQ, drawn through point M Since PQ || RS, AB || RS Since AB || PQ and MX is the transversal XMB + QXM = 180 XMB + 135 = 180 XMB = 180 135 XMB = 45 Similarly, Since AB || RS and MY is the transversal BMY = RYM BMY = 40 Now, XMY = XMB + MBY XMY = 45 + 40 XMY = 85
  1. Chapter 6 Class 9 Lines and Angles
  2. Serial order wise

    3. Examples

    Theorems →
Theorems →
Chapter 6 Class 9 Lines and Angles
Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo