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Example 16 - Chapter 10 Class 6 Mensuration

Last updated at March 16, 2023 by

Example 16 - Bob wants to cover the floor of a room 3 m wide and 4 m

Example 16 - Chapter 10 Class 6 Mensuration - Part 2
Example 16 - Chapter 10 Class 6 Mensuration - Part 3 Example 16 - Chapter 10 Class 6 Mensuration - Part 4

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Example 16 Bob wants to cover the floor of a room 3 m wide and 4 m long by squared tiles. If each square tile is of side 0.5 m, then find the number of tiles required to cover the floor of the room. Here, Number of tiles = (π‘‡π‘œπ‘‘π‘Žπ‘™ π‘Žπ‘Ÿπ‘’π‘Ž π‘œπ‘“ π‘Ÿπ‘’π‘π‘‘π‘Žπ‘›π‘”π‘’π‘™π‘Žπ‘Ÿ π‘Ÿπ‘œπ‘œπ‘š)/(π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“π‘ π‘žπ‘’π‘Žπ‘Ÿπ‘’ 𝑑𝑖𝑙𝑒) Finding area of rectangular room and square tile Rectangular room Length of rectangular room = l = 4 m Breadth of rectangular room = b = 3 m Area of room = l Γ— b = 4 Γ— 3 = 12 sq. m = 12 π‘š^2 Square tile Side of square tile = a = 0.5 m Area of tile = a Γ— a = 0.5 Γ— 0.5 = 5/10 Γ— 5/10 = 25/100 sq m2 Now, Number of tiles = (π‘‡π‘œπ‘‘π‘Žπ‘™ π‘Žπ‘Ÿπ‘’π‘Ž π‘œπ‘“ π‘Ÿπ‘’π‘π‘‘π‘Žπ‘›π‘”π‘’π‘™π‘Žπ‘Ÿ π‘Ÿπ‘œπ‘œπ‘š)/(π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ 𝑑𝑖𝑙𝑒𝑠 π‘ π‘žπ‘’π‘Žπ‘Ÿπ‘’) = 12/(25/100) = 12 Γ— 100/25 = 12 Γ— 4 = 48 ∴ 48 tiles are required to cover the room

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.