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  1. Chapter 10 Class 6 Mensuration
  2. Serial order wise

Transcript

Example 16 Bob wants to cover the floor of a room 3 m wide and 4 m long by squared tiles. If each square tile is of side 0.5 m, then find the number of tiles required to cover the floor of the room. Here, Number of tiles = (๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘Ž๐‘Ÿ๐‘’๐‘Ž ๐‘œ๐‘“ ๐‘Ÿ๐‘’๐‘๐‘ก๐‘Ž๐‘›๐‘”๐‘ข๐‘™๐‘Ž๐‘Ÿ ๐‘Ÿ๐‘œ๐‘œ๐‘š)/(๐ด๐‘Ÿ๐‘’๐‘Ž ๐‘œ๐‘“๐‘ ๐‘ž๐‘ข๐‘Ž๐‘Ÿ๐‘’ ๐‘ก๐‘–๐‘™๐‘’) Finding area of rectangular room and square tile Rectangular room Length of rectangular room = l = 4 m Breadth of rectangular room = b = 3 m Area of room = l ร— b = 4 ร— 3 = 12 sq. m = 12 ๐‘š^2 Square tile Side of square tile = a = 0.5 m Area of tile = a ร— a = 0.5 ร— 0.5 = 5/10 ร— 5/10 = 25/100 sq m2 Now, Number of tiles = (๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘Ž๐‘Ÿ๐‘’๐‘Ž ๐‘œ๐‘“ ๐‘Ÿ๐‘’๐‘๐‘ก๐‘Ž๐‘›๐‘”๐‘ข๐‘™๐‘Ž๐‘Ÿ ๐‘Ÿ๐‘œ๐‘œ๐‘š)/(๐ด๐‘Ÿ๐‘’๐‘Ž ๐‘œ๐‘“ ๐‘ก๐‘–๐‘™๐‘’๐‘  ๐‘ ๐‘ž๐‘ข๐‘Ž๐‘Ÿ๐‘’) = 12/(25/100) = 12 ร— 100/25 = 12 ร— 4 = 48 โˆด 48 tiles are required to cover the room

About the Author

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.