Example 3 - Practical Geometry

Last updated at Dec. 16, 2024 by

Example 3 - Construct XYZ if it is given that XY = 6 cm, ZXY = 30

Example 3 - Chapter 10 Class 7 Practical Geometry - Part 2
Example 3 - Chapter 10 Class 7 Practical Geometry - Part 3
Example 3 - Chapter 10 Class 7 Practical Geometry - Part 4
Example 3 - Chapter 10 Class 7 Practical Geometry - Part 5

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Transcript

Example 3 Construct ∆XYZ if it is given that XY = 6 cm, m∠ZXY = 30° and m∠XYZ = 100°. First we draw a rough sketch We follow these steps Steps of construction 1. Draw a line segment XY of length 6 cm 2. Now, we draw 30° from point X Check Ex 11.1, 3 (i) of Chapter 11 Class 9 NCERT to see how to draw 30° 3. Now, we draw 100° from point Y (Using protractor) 4. Let point Z be the point where the two rays intersect and label the sides Thus, Δ XYZ is the required triangle

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo