Example 1 - Practical Geometry

Last updated at July 27, 2026 by

Example 1 - Construct triangle ABC, given AB = 5 cm, BC = 6 cm, AC = 7

Example 1 - Chapter 10 Class 7 Practical Geometry - Part 2
Example 1 - Chapter 10 Class 7 Practical Geometry - Part 3 Example 1 - Chapter 10 Class 7 Practical Geometry - Part 4 Example 1 - Chapter 10 Class 7 Practical Geometry - Part 5

Remove Ads

Transcript

Example 1 Construct a triangle ABC, given that AB = 5 cm, BC = 6 cm and AC = 7 cm. First we draw a rough sketch We follow these steps Steps of construction 1. Draw a line segment AB of length 5 cm 2. Taking 7 cm as radius, and A as center, draw an arc. 3. Taking 6 cm as radius, and B as center, draw another arc. Let C be the point where the two arcs intersect Join AC and BC and label the sides Thus, Δ ABC is the required triangle

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.