# Example 1 - Chapter 10 Class 7 Practical Geometry

Last updated at Oct. 1, 2018 by Teachoo

Last updated at Oct. 1, 2018 by Teachoo

Transcript

Example 1 Construct a triangle ABC, given that AB = 5 cm, BC = 6 cm and AC = 7 cm. First we draw a rough sketch We follow these steps Steps of construction 1. Draw a line segment AB of length 5 cm 2. Taking 7 cm as radius, and A as center, draw an arc. 3. Taking 6 cm as radius, and B as center, draw another arc. Let C be the point where the two arcs intersect Join AC and BC and label the sides Thus, Δ ABC is the required triangle

Constructing a triangle when 3 sides known (SSS)

Chapter 10 Class 7 Practical Geometry

Concept wise

- Construction of line parallel to given line, through point not on line
- Constructing a triangle when 3 sides known (SSS)
- Constructing a triangle when 2 sides and angle between is known (SAS)
- Constructing a triangle when 2 angles and side between is known (ASA)
- Constructing a right triangle when hypotenuse and side is given (RHS)

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.