Ex 10.5, 3 - Construct an isosceles right-angled triangle ABC

Ex 10.5, 3 - Chapter 10 Class 7 Practical Geometry - Part 2
Ex 10.5, 3 - Chapter 10 Class 7 Practical Geometry - Part 3 Ex 10.5, 3 - Chapter 10 Class 7 Practical Geometry - Part 4 Ex 10.5, 3 - Chapter 10 Class 7 Practical Geometry - Part 5

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Question 3 Construct an isosceles right-angled triangle ABC, where m∠ACB = 90° and AC = 6 cm. Given Δ ABC where ∠ C = 90° AC = 6 cm Also, Δ ABC is isosceles Now, in a right angle triangle, Hypotenuse is the largest side. So, it can’t be equal to any other side ∴ BC = AC = 6 cm Let’s construct it Steps of construction 1. Draw a line segment AC of length 6 cm 2. Now, we draw 90° from point C Check Ex 11.1, 1 of Chapter 11 Class 9 NCERT to see how to draw 90° 3. Taking C as center, 6 cm as radius, we draw an arc Let the point where arc intersects the ray be point B 4. Join BA and label the sides Thus, Δ ABC is the required triangle

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.