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  1. Chapter 12 Class 6 Ratio And Proportion
  2. Serial order wise
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Ex 12.1, 14 (Method 1) Divide 20 pens between Sheela and Sangeeta in the ratio of 3 : 2. Total number of pens = 20 Given Ratio = 3 : 2 (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘’๐‘›๐‘  ๐‘ค๐‘–๐‘กโ„Ž ๐‘†โ„Ž๐‘’๐‘’๐‘™๐‘Ž)/(๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘’๐‘›๐‘  ๐‘ค๐‘–๐‘กโ„Ž ๐‘†๐‘Ž๐‘›๐‘”๐‘’๐‘’๐‘ก๐‘Ž) = 3/2 Number of pens with Sheela = 3/2 ร— Number of pens with Sangeeta Now, Total number of pens = Number of pens with Sheela + Number of pens with Sangeeta 20 = 3/2 Number of pens with Sangeeta + Number of pens with Sangeeta 20 = (3/2+1) Number of pens with Sangeeta 20 = ((3 + 2)/2) Number of pens with Sangeeta 20 = 5/2 ร— Number of pens with Sangeeta 20 ร— 2/5 = Number of pens with Sangeeta 4 ร— 2 = Number of pens with Sangeeta 8 = Number of pens with Sangeeta Number of pens with Sangeeta = 8 pens Also, Number of pens with Sheela = 3/2 ร— Number of pens with Sangeeta = 3/2 ร— 8 = 3 ร— 4 = 12 pens Ex 12.1, 14 (Method 2) Divide 20 pens between Sheela and Sangeeta in the ratio of 3 : 2.Total number of pens = 20 Given Ratio = 3 : 2 (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘’๐‘›๐‘  ๐‘ค๐‘–๐‘กโ„Ž ๐‘†โ„Ž๐‘’๐‘’๐‘™๐‘Ž)/(๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘’๐‘›๐‘  ๐‘ค๐‘–๐‘กโ„Ž ๐‘†๐‘Ž๐‘›๐‘”๐‘’๐‘’๐‘ก๐‘Ž) = 3/2 which means 3 parts of total pens goes to Sheela and 2 parts of total pens goes to Sangeeta So, pens are divided in = 3 + 2 = 5 parts From which, Sheela gets 3 parts out of 5 parts and Sangeeta gets 2 parts out of 5 parts Number of pens with Sheela = 3/5 ร— 20 = 3 ร— 4 = 12 pens Number of pens with Sangeeta = 2/5 ร— 20 = 2 ร— 4 = 8 pens

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.