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Ex 12.1

Ex 12.1, 1

Ex 12.1, 2 Important

Ex 12.1, 3

Ex 12.1, 4 Important

Ex 12.1, 5 Important

Ex 12.1, 6 (a)

Ex 12.1, 6 (b) Important

Ex 12.1, 6 (c)

Ex 12.1, 6 (d) Important

Ex 12.1, 7 (a) Important

Ex 12.1, 7 (b)

Ex 12.1, 7 (c) Important

Ex 12.1, 7 (d) Important

Ex 12.1, 8

Ex 12.1, 9

Ex 12.1, 10 Important

Ex 12.1, 11

Ex 12.1, 12 Important

Ex 12.1, 13 Important

Ex 12.1, 14 You are here

Ex 12.1, 15 Important

Ex 12.1, 16 Important

Last updated at March 16, 2023 by Teachoo

Ex 12.1, 14 (Method 1) Divide 20 pens between Sheela and Sangeeta in the ratio of 3 : 2. Total number of pens = 20 Given Ratio = 3 : 2 (๐๐ข๐๐๐๐ ๐๐ ๐๐๐๐ ๐ค๐๐กโ ๐โ๐๐๐๐)/(๐๐ข๐๐๐๐ ๐๐ ๐๐๐๐ ๐ค๐๐กโ ๐๐๐๐๐๐๐ก๐) = 3/2 Number of pens with Sheela = 3/2 ร Number of pens with Sangeeta Now, Total number of pens = Number of pens with Sheela + Number of pens with Sangeeta 20 = 3/2 Number of pens with Sangeeta + Number of pens with Sangeeta 20 = (3/2+1) Number of pens with Sangeeta 20 = ((3 + 2)/2) Number of pens with Sangeeta 20 = 5/2 ร Number of pens with Sangeeta 20 ร 2/5 = Number of pens with Sangeeta 4 ร 2 = Number of pens with Sangeeta 8 = Number of pens with Sangeeta Number of pens with Sangeeta = 8 pens Also, Number of pens with Sheela = 3/2 ร Number of pens with Sangeeta = 3/2 ร 8 = 3 ร 4 = 12 pens Ex 12.1, 14 (Method 2) Divide 20 pens between Sheela and Sangeeta in the ratio of 3 : 2.Total number of pens = 20 Given Ratio = 3 : 2 (๐๐ข๐๐๐๐ ๐๐ ๐๐๐๐ ๐ค๐๐กโ ๐โ๐๐๐๐)/(๐๐ข๐๐๐๐ ๐๐ ๐๐๐๐ ๐ค๐๐กโ ๐๐๐๐๐๐๐ก๐) = 3/2 which means 3 parts of total pens goes to Sheela and 2 parts of total pens goes to Sangeeta So, pens are divided in = 3 + 2 = 5 parts From which, Sheela gets 3 parts out of 5 parts and Sangeeta gets 2 parts out of 5 parts Number of pens with Sheela = 3/5 ร 20 = 3 ร 4 = 12 pens Number of pens with Sangeeta = 2/5 ร 20 = 2 ร 4 = 8 pens From which, Sheela gets 3 parts out of 5 parts and Sangeeta gets 2 parts out of 5 parts Number of pens with Sheela = 3/5 ร 20 = 3 ร 4 = 12 pens Number of pens with Sangeeta = 2/5 ร 20 = 2 ร 4 = 8 pens