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Ex 6.5, 1 - PQR is a triangle, right-angled at P. If PQ = 10 cm

Ex 6.5, 1 - Chapter 6 Class 7 Triangle and its Properties - Part 2

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Transcript

Ex 6.5, 1 PQR is a triangle, right-angled at P. If PQ = 10 cm and PR = 24 cm, find QR.In βˆ†PQR, right angled at P, PR = 24 cm, PQ = 10 cm, QR = ? By Pythagoras theorem, 〖𝑄𝑅〗^2 = 〖𝑃𝑄〗^2 + 〖𝑃𝑅〗^2 〖𝑄𝑅〗^2 = γ€–(10)γ€—^2 + γ€–(24)γ€—^2 〖𝑄𝑅〗^2 = 100 + 576 〖𝑄𝑅〗^2 = 676 〖𝑄𝑅〗^2 = γ€–(26)γ€—^2 Cancelling squares 𝑄𝑅 = 26 ∴ 𝑸𝑹 = 26 Rough 676 = 2 Γ— 2 Γ— 13 Γ— 13 = (2 Γ— 13) Γ— (2 Γ— 13) = 26 Γ— 26 = 262

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.