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  1. Chapter 6 Class 8 Squares and Square Roots
  2. Serial order wise
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Transcript

Ex 6.1, 5 Observe the following pattern and supply the missing numbers. 〖11〗^2 = 1 2 1 〖 101〗^2 = 1 0 2 0 1 〖 10101〗^2 = 102030201 〖1010101〗^2 = ........................... 〖"................" 〗^2= 10203040504030201 1012 = 10201 Number of 1s in 101 is = 2 So we write numbers upto 2 & then decrease 1012 = Now, Adding 1 zero between the Digits 1012 = 101012 = 102030201 Number of 1s in 101 is = 3 So we write numbers upto 3 & then decrease 101012 = Now, Adding 1 zero between the Digits 101012 = 10101012 = ………….. Number of 1s in 101 is = 4 So we write numbers upto 4 & then decrease 10101012 = Now, Adding 1 zero between the Digits 10101012 = 〖"................" 〗^2= 10203040504030201 Since number on left is till 5 Number of 1s on left number = 5 and we will add one zero between it The number will be = 10203040504030201

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.