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Ex 6.1, 5 - Observe the following pattern and supply the missing

Ex 6.1, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 2
Ex 6.1, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 3 Ex 6.1, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 4

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Ex 6.1, 5 Observe the following pattern and supply the missing numbers. 〖11〗^2 = 1 2 1 〖 101〗^2 = 1 0 2 0 1 〖 10101〗^2 = 102030201 〖1010101〗^2 = ........................... 〖"................" 〗^2= 10203040504030201 1012 = 10201 Number of 1s in 101 is = 2 So we write numbers upto 2 & then decrease 1012 = Now, Adding 1 zero between the Digits 1012 = 101012 = 102030201 Number of 1s in 101 is = 3 So we write numbers upto 3 & then decrease 101012 = Now, Adding 1 zero between the Digits 101012 = 10101012 = ………….. Number of 1s in 101 is = 4 So we write numbers upto 4 & then decrease 10101012 = Now, Adding 1 zero between the Digits 10101012 = 〖"................" 〗^2= 10203040504030201 Since number on left is till 5 Number of 1s on left number = 5 and we will add one zero between it The number will be = 10203040504030201

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.