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Last updated at Feb. 20, 2019 by Teachoo

Transcript

Example 3 Find the digits A & B Here, A × 3 ends with A We put different values of A, and check which ends with A ∴ A can be 0, or 5 Checking for A = 0, B = 9 Putting values Since multiplication is not 570 ∴ A = 0 is not possible Checking for A = 0, B = 9 Putting values Since multiplication is not 570 ∴ A = 0 is not possible For A = 5 Calculating Multiplication Here, (3B + 1) + 5B ends with 7 i.e. 8B + 1 ends with 7 Checking different values of B ∴ B = 2 Checking for A = 5, B = 2 Putting values Hence verified ∴ A = 5 and B = 2

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.