Check sibling questions

Ex 16.1, 4 - Find the values of letters - A B + 3 7 = 6A

Ex 16.1, 4 - Chapter 16 Class 8 Playing with Numbers - Part 2
Ex 16.1, 4 - Chapter 16 Class 8 Playing with Numbers - Part 3

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Ex 16.1, 4 Find the values of the letters in each of the following and give reasons for the steps involved. Here, B can be 0, 1, 2,……….., 9 So, B + 7 can be 7, 8, 9,…………,16. So either A + 3 = 6 or 1 + A + 3 = 6 A + 3 = 6 A = 6 − 3 A = 3 Now, Finding B Here, B = 6, but A ≠ 3 So, it is not possible 1 + A + 3 = 6 A + 4 = 6 A = 6 − 4 A = 2 Now, Finding B Here, ∴ B = 5 Thus, A = 2 and B = 5 Checking Putting A = 2, B = 5 Hence Verified ∴ A = 2 and B = 5

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.