# Ex 3.1, 5 - Chapter 3 Class 7 Data Handling

Last updated at July 13, 2018 by Teachoo

Last updated at July 13, 2018 by Teachoo

Ex 3.1, 5 Following table shows the points of each player scored in four games: Now answer the following questions: (i) Find the mean to determine Aβs average number of points scored per game. Average points of A = (πππ‘ππ πππππ‘π ππ π΄ ππ πππ πππππ )/(ππ’ππππ ππ πππππ π΄ ππππ¦ππ) = (14 + 16 + 10 + 10)/4 = 50/4 = 25/2 = 12.5 Ex 3.1, 5 Following table shows the points of each player scored in four games: Now answer the following questions: (ii) To find the mean number of points per game for C, would you divide the total points by 3 or by 4? Why? Mean points of C = (πππ‘ππ πππππ‘π ππ πΆ ππ πππ πππππ )/(ππ’ππππ ππ πππππ πΆ ππππ¦ππ) Number of games C played = 3 So, we divide the total by 3 Letβs also find the mean of C Mean points of C = (πππ‘ππ πππππ‘π ππ πΆ ππ πππ πππππ )/(ππ’ππππ ππ πππππ πΆ ππππ¦ππ) = (8 + 11 + 13)/3 = 32/3 = 10.66.. Ex 3.1, 5 Following table shows the points of each player scored in four games: Now answer the following questions: (iii) B played in all the four games. How would you find the mean?Mean = (πππ‘ππ πππππ‘π ππ π΅)/(ππ’ππππ ππ πππππ π΅ ππππ¦ππ) = (0 + 8 + 6 + 4)/4 = 18/4 = 4.5 Ex 3.1, 5 Following table shows the points of each player scored in four games: Now answer the following questions: (iv) Who is the best performer? Mean of A = 12.5 Mean of B = 4.5 Mean of C = 10.66 Since mean of A is highest, A is the best performer