Example 7 - Chapter 8 Class 6 Decimals

Last updated at August 2, 2026 by

Example 7 - Kanchan bought a watermelon weighing 5 kg 200 g. Out of - Examples

part 2 - Example 7 - Examples - Serial order wise - Chapter 8 Class 6 Decimals

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Example 7 Kanchan bought a watermelon weighing 5 kg 200 g. Out of this she gave 2 kg 750 g to her neighbour. What is the weight of the watermelon left with Kanchan? Total weight = 5 kg Amount given to neighbour = 2 kg 750 g Amount left = 5 kg 200 g – 2kg 750 g = (5 kg + 200 g) – (200g – 750 g) = (5 kg – 2 kg) + (200 g – 750 g) = 3 kg – (–200 g +750 g) = 3 kg – (750 – 200) g = 3 kg – 550 g = 3 kg – 550 × 1 g = 3kg – 550 × 1/1000 kg = 3 – 𝟓𝟓𝟎/𝟏𝟎𝟎𝟎 kg = (3 × 1000)/1000 – 550/1000 kg = ((3000 − 550))/1000 = 𝟐𝟒𝟓𝟎/𝟏𝟎𝟎𝟎 = 2.450 ∴ Amount left = 2.450 kg

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