Ex 4.1, 2 - Check whether the value given in brackets is a solution

Ex 4.1, 2 - Chapter 4 Class 7 Simple Equations - Part 2
Ex 4.1, 2 - Chapter 4 Class 7 Simple Equations - Part 3
Ex 4.1, 2 - Chapter 4 Class 7 Simple Equations - Part 4
Ex 4.1, 2 - Chapter 4 Class 7 Simple Equations - Part 5 Ex 4.1, 2 - Chapter 4 Class 7 Simple Equations - Part 6

Go Ad-free

Transcript

Ex 4.1, 2 Check whether the value given in the brackets is a solution to the given equation or not: (a) n + 5 = 19 (n = 1) n + 5 = 19 Putting n = 1 1 + 5 = 19 6 = 19 It is not true. Hence, n = 1 is not a solution. Ex 4.1, 2 Check whether the value given in the brackets is a solution to the given equation or not: (b) 7n + 5 = 19 (n = – 2) 7n + 5 = 19 Putting n = −2 7 (−2) + 5 = 19 −14 + 5 = 19 −(14 − 5) = 19 −9 = 19 It is not true. Hence, n = −2 is not a solution. Ex 4.1, 2 Check whether the value given in the brackets is a solution to the given equation or not: (c) 7n + 5 = 19 (n = 2) 7n + 5 = 19 Putting n = 2 7 (2) + 5 = 19 14 + 5 = 19 19 = 19 It is true. Hence, n = 2 is a solution. Ex 4.1, 2 Check whether the value given in the brackets is a solution to the given equation or not: (d) 4p – 3 = 13 (p = 1) 4p − 3 = 13 Putting p = 1 4(1) + 3 = 13 4 − 3 = 13 1 = 13 It is not true. Hence, p = 1 is not a solution. Ex 4.1, 2 Check whether the value given in the brackets is a solution to the given equation or not: (e) 4p – 3 = 13 (p = – 4) 4p − 3 = 13 Putting p = −4 4(−4) − 3 = 13 −16 − 3 = 13 −(16 + 3) = 13 −19 = 13 It is not true. Hence, p = −4 is not a solution. Ex 4.1, 2 Check whether the value given in the brackets is a solution to the given equation or not: (f) 4p – 3 = 13 (p = 0) 4p − 3 = 13 Putting p = 0 4(0) − 3 = 13 0 − 3 = 13 −3 = 13 It is not true. Hence, p = 0 is not a solution.

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.