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Ex 11.2, 2

Construct a triangle ABC in which BC = 8 cm, ∠B = 45°  and AB − AC = 3.5 cm.

Given, in Δ ABC,

BC = 8 cm ∠B = 45° and AB – AC = 3.5 cm

Steps of Construction

  1. Draw base BC  = 8 cm and at point B make an ∠ XBC = ∠ B = 45°
  2. Cut a line segment BD equal to AB – AC from ray BX
  3. Join DC. Draw perpendicular bisector.
    PQ of line DC.
  4. Let PQ intersect BX a point A. Join AC.

Then, Δ ABC is the required triangle.

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  1. Chapter 11 Class 9 Constructions
  2. Concept wise
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CA Maninder Singh
CA Maninder Singh is a Chartered Accountant for the past 7 years. He provides courses for Practical Accounts, Taxation and Efiling at teachoo.com .
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