1. Chapter 11 Class 9 Constructions
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Ex 11.2, 2 Construct a triangle ABC in which BC = 8 cm, ∠B = 45°  and AB − AC = 3.5 cm. Given, in Δ ABC, BC = 8 cm ∠B = 45° and AB – AC = 3.5 cm Steps of Construction Draw base BC  = 8 cm and at point B make an ∠ XBC = ∠ B = 45° Cut a line segment BD equal to AB – AC from ray BX Join DC. Draw perpendicular bisector. PQ of line DC. Let PQ intersect BX a point A. Join AC. Then, Δ ABC is the required triangle.

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