Ex 10.2, 7 - Chapter 10 Class 11 Conic Sections

Last updated at July 21, 2026 by

Ex 10.2, 7 - Find equation of parabola: Focus (6,0), x = -6 - Ex 10.2

part 2 - Ex 10.2, 7 - Ex 10.2 - Serial order wise - Chapter 10 Class 11 Conic Sections

Remove Ads

Transcript

Ex 10.2, 7 Find the equation of the parabola that satisfies the following conditions: Focus (6, 0); directrix x = 6 Since focus lies on x-axis Hence equation is either y2 = 4ax or y2 = 4ax Now focus has positive x co-ordinate So, we have to use equation y2 = 4ax Coordinate of focus = (a, 0) (a, 0) = (6, 0) a = 6 Hence equation of parabola is y2 = 4ax y2 = 4(6)x y2 = 24x

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.