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Question 2 - Figure it out - Page 175 - Chapter 7 Class 8 - Proportional Reasoning-1(Ganita Prakash)
Last updated at August 14, 2026 by Teachoo
Figure it out - Page 175
Ganita Prakash Class 8 - Part 1, 2
Chapter 7 Class 8 - Proportional Reasoning-1 (Ganita Prakash)
- Observing Similarity in Change
- Basic Definitions
- Problem Solving with Proportional Reasoning
- Figure it out - Page 165-167
- TrairasikaβThe Rule of Three
- Figure it out - Page 170-171
- Acitvity and Question - Page 171
- Sharing, but Not Equally!
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Figure it out - Page 175
- Unit Conversion
- Figure it out - Page 176, 177
Transcript
Question 2 In a science lab, acid and water are mixed in the ratio of 1 : 5 to make a solution. In a bottle that has 240 mL of the solution, how much acid and water does the solution contain?Given that acid and water are mixed in the ratio of 1 : 5 So, we can write Amount of Acid : Amount of Water = 1 : 5 Converting into fractions (π¨πππππ ππ π¨πππ )/(π¨πππππ ππ πΎππππ )=π/π Cross multiplying 5 Γ Amount of Acid = Amount of Water Amount of Water = 5 Γ Amount of Acid Now, Total solution = 240 mL Amount of Acid + Amount of water = 240 Putting Amount of Water = 5 Γ Amount of Acid Amount of Acid + 5 Γ Amount of Acid = 240 Amount of Acid Γ (1 + 5) = 240 Amount of Acid Γ 6 = 240 Amount of Acid = 240/6 Amount of Acid = 40 mL Thus, Amount of Water = 5 Γ Amount of Acid = 5 Γ 40 = 200 mL Thus, the solution contains 40 mL of acid and 200 mL of water.
