Example 3 - Chapter 7 Class 8 - Proportional Reasoning-1(Ganita Prakash)

Transcript

Example 3 Nitin and Hari were constructing a compound wall around their house. Nitin was building the longer side, 60 ft in length, and Hari was building the shorter side, 40 ft in length. Nitin used 3 bags of cement but Hari used only 2 bags of cement. Nitin was worried that the wall Hari built would not be as strong as the wall he built because she used less cement. Let’s find Ratio of Length of Wall to Number of bags of cement used by both Nitin and Hari Nitin Nitin built wall of 60 ft using 3 bags of cement Ratio of Nitin = 60 : 3 Hari Hair built wall of 40 ft using 2 bags of cement Ratio of Nitin = 40 : 2 Now, it says that Nitin was worried that the wall Hari built would not be as strong as the wall he built because she used less cement So, we need to compare the two ratios To compare, we find Simplest form of Ratios for both Nitin Ratio 60 : 3 = 60/3 = 20/1 = 20 : 1 Hari Ratio 40 : 2 = 40/2 = 20/1 = 20 : 1 Both Ratios are the same This means that both used exactly 1 bag for every 20 ft, So, both the walls are equally strong.