You are here
![Filling 3 × 3 grid – Question 2 Page 133 - [Class 7 Ganita Prakash] - Some Explorations in Grids](https://cdn.teachoo.com/01db9fdc-a36a-41da-b213-c921f0a65a23/slide9.jpg)
Filling 3 × 3 grid – Question 2 Page 133
Last updated at October 17, 2025 by Teachoo
Class 7 (Ganita Prakash 1, 2 & old NCERT)
Chapter 6 Class 7 - Number Play - Ganita Prakash
- Numbers can Tell us Things, Supercells
- Parity
- Figure it out - Page 131
- Small Squares in Grids (Parity in Multiplication)
- Parity of Expressions
-
Some Explorations in Grids
- Magic Square
- Figure it out - Page 136
- Generalising 3 × 3 Magic Square
- First ever 4 × 4 Magic Square
- Magic Squares in History and Culture
- Virahāṅka Fibonacci Numbers
- Digits in Disguise
- Figure it out - Page 143, 144
Transcript
Filling grid – Question 2 Page 133 Fill this 3 × 3 grid Let us name the remaining numbers Sum of 2nd row 4 + d + g = 15 d + g = 15 – 4 d + g = 11 Since sum of 3rd column is greater Let g be bigger than d ∴ d = 5, g = 6 Sum of 3rd row b + e + 3 = 6 b + e = 6 – 3 b + 3 = 3 Since sum of 2nd column is greater Let e be bigger than b ∴ b = 1 , e = 2 Sum of 1st column a + 4 + 1 = 12 a + 5 = 12 a = 12 – 5 a = 7 Sum of 2nd column c + 5 + 2 = 16 c + 7 = 16 c = 16 – 7 c = 9 Sum of 3rd column f + 6 + 3 = 17 f + 9 = 17 f = 17 – 9 f = 8 Thus, our final grid is
