





Power Lines
Last updated at Aug. 18, 2025 by Teachoo
Transcript
Power Line of 7Power line of 7 looks like Power is decreasing as we go down β (7^7&-&823543@7^6&-&117649@7^5&-&16807@7^4&-&2401@7^3&-&343@7^2&-&49@7^1&-&7@7^0&-&1@7^(-1)&-&1/7@7^(-2)&-&1/49@7^(-3)&-&1/343@7^(-4)&-&1/2401)We need to answer some questions 2,401 Γ 49? 493 = ? 343 Γ 2,401 = ? (ππ,πππ)/ππ = ? π/πππ = ? (ππ,πππ)/(π,ππ,πππ) = ? 1,17,649 Γ π/πππ = ? π/πππ Γ π/πππ = ? Letβs answer them one by one 2,401 Γ 49? 2,401 Γ 49 = π^π Γ π^π = π^(π+π) = 7^6 = 1,17,649 493 = ? 493 = γ(π^π)γ^π = π^(π Γ π) = 7^6 = 1,17,649 π/πππ " = ?" 7/343 = 7^1/7^3 = π^(πβπ) = 7^(β2) = π/ππ (ππ,πππ)/(π,ππ,πππ) = ? 16,807/8,23,543 = 7^5/7^7 = π^(πβπ) = 7^(β2) = π/ππ 343 Γ 2,401 = ? 343 Γ 2,401 = π^π Γ π^π = π^(π+π) = 7^7 = 8,23,543 (ππ,πππ)/ππ = ? 16,807/49 = 7^5/7^2 = π^(πβπ) = 7^3 = 343 1,17,649 Γ π/πππ = ? 1,17,649 Γ 1/343 = π^π Γπ^(βπ) = 7^(7 + (β3)) = π^(π β π) = 7^4 = 2,401 π/πππ Γ π/πππ = ? 1/343 " Γ " 1/343 = π^(βπ) Γ π^(βπ) = 7^(β3 + (β3)) = π^(βπ β π) = 7^(β(3+ 3)) = π^(βπ) = 1/7^6 = π/(π,ππ,πππ)