Use this observation (๐‘›^๐‘Ž  × ๐‘›^๐‘=๐‘›^(๐‘Ž+๐‘)) to compute -  (i) 2^9 - Formulas of Exponents

part 2 - Question 1 (Page 24) - Formulas of Exponents - Chapter 2 Class 8 - Power Play (Ganita Prakash) - Class 8 (Ganita Prakash & Old NCERT)
part 3 - Question 1 (Page 24) - Formulas of Exponents - Chapter 2 Class 8 - Power Play (Ganita Prakash) - Class 8 (Ganita Prakash & Old NCERT)

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Question 1 (Page 24) Use this observation (๐‘›^๐‘Ž ร— ๐‘›^๐‘=๐‘›^(๐‘Ž+๐‘)) to compute the following. (i) 29 We divide the main power as a sum of two/three/four powers which we can easily calculate Now, ๐Ÿ^๐Ÿ—=๐Ÿ^(๐Ÿ‘ +๐Ÿ‘ + ๐Ÿ‘) =๐Ÿ^๐Ÿ‘ ร— ๐Ÿ^๐Ÿ‘ร— ๐Ÿ^๐Ÿ‘ =8 ร— 8 ร— 8 =64 ร— 8 =๐Ÿ“๐Ÿ๐Ÿ Question 1 (Page 24) Use this observation (๐‘›^๐‘Ž ร— ๐‘›^๐‘=๐‘›^(๐‘Ž+๐‘)) to compute the following. (ii) 57We divide the main power as a sum of two/three/four powers which we can easily calculate Now, ๐Ÿ“^๐Ÿ•=๐Ÿ“^(๐Ÿ + ๐Ÿ + ๐Ÿ‘) =๐Ÿ“^๐Ÿ ร— ๐Ÿ“^๐Ÿร— ๐Ÿ“^๐Ÿ‘ =25 ร— 25 ร— 125 =625 ร— 125 =๐Ÿ•๐Ÿ–๐Ÿ๐Ÿ๐Ÿ“ Question 1 (Page 24) Use this observation (๐‘›^๐‘Ž ร— ๐‘›^๐‘=๐‘›^(๐‘Ž+๐‘)) to compute the following. (iii) 46We divide the main power as a sum of two/three/four powers which we can easily calculate Now, ๐Ÿ’^๐Ÿ”=๐Ÿ’^(๐Ÿ + ๐Ÿ + ๐Ÿ) =๐Ÿ’^๐Ÿ ร— ๐Ÿ’^๐Ÿร— ๐Ÿ’^๐Ÿ =16 ร— 16 ร— 16 =256 ร— 16 =๐Ÿ’๐ŸŽ๐Ÿ—๐Ÿ”

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CA Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 15 years. He also provides Accounts Tax GST Training in Delhi, Kerala and online.