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Question 6 - Figure it out - Page 10, 11 - Chapter 1 Class 8 - A Square and a Cube (Ganita Prakash)
Last updated at July 30, 2025 by Teachoo
Class 8 (Ganita Prakash & Old NCERT)
Chapter 1 Class 8 - A Square and a Cube (Ganita Prakash)
- Introduction
- Square Numbers
- Perfect Squares - and its Properties
- Perfect Squares - and its Patterns
- Square Root
- Smallest number multiply or divide to get perfect square
- Estimating Square Root
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Figure it out - Page 10, 11
- Cubic Numbers
- Perfect Cubes - and its Properties
- Perfect Cubes - and its Patterns
- Cube Root
- Smallest number multiply or divide to get perfect cube
- A pinch of History
- Figure it out - Page 16, 17
Transcript
Question 6 Find the smallest number by which 9408 must be multiplied so that the product is a perfect square. Find the square root of the product. Prime factorizing 9408 We see that , 9408 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 7 × 7 Since 3 does not occur in pairs, we multiply by 3 to make it a pair So, our number becomes 9408 × 3 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 7 × 7 × 3 28224 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 7 × 7 Square root of 28224 ∴ √28224 = 2 × 2 × 2 × 3 × 7 = 168 ∴ The smallest whole number to be multiplied = 3 and square root of new number = 168
