Find the Remainders obtained When Numbers Are Divided by 10, 5, and 2 - Figure it out - Page 125, 126

part 2 - Question 4 - Figure it out - Page 125, 126 - Chapter 5 Class 6 - Prime Time (Ganita Prakash) - Class 6 (Ganit Prakash)
part 3 - Question 4 - Figure it out - Page 125, 126 - Chapter 5 Class 6 - Prime Time (Ganita Prakash) - Class 6 (Ganit Prakash)
part 4 - Question 4 - Figure it out - Page 125, 126 - Chapter 5 Class 6 - Prime Time (Ganita Prakash) - Class 6 (Ganit Prakash)
part 5 - Question 4 - Figure it out - Page 125, 126 - Chapter 5 Class 6 - Prime Time (Ganita Prakash) - Class 6 (Ganit Prakash) part 6 - Question 4 - Figure it out - Page 125, 126 - Chapter 5 Class 6 - Prime Time (Ganita Prakash) - Class 6 (Ganit Prakash) part 7 - Question 4 - Figure it out - Page 125, 126 - Chapter 5 Class 6 - Prime Time (Ganita Prakash) - Class 6 (Ganit Prakash) part 8 - Question 4 - Figure it out - Page 125, 126 - Chapter 5 Class 6 - Prime Time (Ganita Prakash) - Class 6 (Ganit Prakash)

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Question 4 Find the remainders obtained when each of the following numbers are divided by (a) 10, (b) 5, (c) 2. 78, 99, 173, 572, 980, 1111, 2345Let’s do this one by one For 78 When divided by 10 Remainder = 8 When divided by 5 Remainder = 3 When divided by 2 Remainder = 0 When divided by 10 Remainder = 9 When divided by 5 Remainder = 4 When divided by 2 Remainder = 1 When divided by 10 Remainder = 3 When divided by 5 Remainder = 3 When divided by 2 Remainder = 1 When divided by 5 Remainder = 2 When divided by 2 Remainder = 0 When divided by 10 Remainder = 2 When divided by 10 Remainder = 0 When divided by 5 Remainder = 0 When divided by 2 Remainder = 0 When divided by 5 Remainder = 1 When divided by 10 Remainder = 1 When divided by 2 Remainder = 1 When divided by 5 Remainder = 0 When divided by 2 Remainder = 1 When divided by 10 Remainder = 5 To summarise For the numbers 78, 99, 173, 572, 980, 1111, 2345: a. Remainder when divided by 10: 8, 9, 3, 2, 0, 1, 5. b. Remainder when divided by 5: 3, 4, 3, 2, 0, 1, 0. c. Remainder when divided by 2: 0, 1, 1, 0, 0, 1, 1.

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo