Question 2 - Figure it out - Page 125, 126 - Chapter 5 Class 6 - Prime Time (Ganita Prakash)

Transcript

Question 2 Find the largest and smallest 4-digit numbers that are divisible by 4 and are also palindromes.Palindromes are numbers that read the same backwards and forwards. Four digit palindrome is like Here, 1st digit and 4th digit should be same 2nd digit and 3rd digit should be same Smallest and largest 4 digit Palindrome divisible by 4 Since number is divisible by 4, last two digits are multiples of 4 So, last two digits could be 04, 08, 12, 16, …., 80, 84, 88, 92, 96 Now, Taking 04, number would be 4004 Taking 08, number would be 8008 Taking 12, number would be 2112 Taking 16, number would be 2116 Taking 20, number would be 0220 (which is 3-digit number) Taking 24, number would be 4224 Taking 28, number would be 8228 Taking 32, number would be 2332 … Taking 80, number would be 0880 (which is 3-digit number) Taking 84, number would be 4884 Taking 88, number would be 8888 Taking 92, number would be 2992 Taking 96, number would be 6996 Thus, Largest 4 digit Palindrome divisible by 4 is 8888 Smallest 4 digit Palindrome divisible by 4 is 2112