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Ex 4.1, 10 - Chapter 4 Class 11 Complex Numbers
Last updated at Dec. 16, 2024 by Teachoo
Identities (square, cube of 2 complex numbers)
Chapter 4 Class 11 Complex Numbers
Concept wise
- Quadaratic equation
- Two complex numbers equal
- Convert to a + ib form
-
Identities (square, cube of 2 complex numbers)
- Division
- Power of i(odd and even)
- Conjugate
- Modulus,argument
- Polar representation
- Proof- Replacing iota with -iota
- Proof- Taking general complex numbers
- Proof- Solving
- Proof- Using modulus conjugate property (Pg 102)
Transcript
Ex 4.1, 10 Express the given Complex number in the form a + ib: (−2−1/3 𝑖)^3 (−2−1/3 𝑖)^3 = − 1 (2+1/3 𝑖)^3 = − (2+1/3 𝑖)^3 It is of the form (a + b)3 Using (a + b)3 = a3 + b3 + 3 ab (a + b) Here a = 2 and b = 1/3 i = −((2)^3+(1/3 𝑖)^3+3 ×2×1/3 𝑖(2+1/3 𝑖)) = −(8+(1/3)^3×(𝑖)^3+2𝑖(2+1/3 𝑖)) = −(8+1/27 𝑖^3+4𝑖+2/3 𝑖^2 ) = −(8+1/27 〖𝑖×𝑖〗^2+4𝑖+2/3 𝑖^2 ) Putting 𝑖^2=−1 = −1 (8+1/27 𝑖(−1)+4𝑖+2/3 (−1)) = −1 (8−1/27 𝑖+4𝑖−2/3) = − 8 + 1/27 𝑖 − 4i + 2/3 = − 8 + 2/3 + ( 1)/27 𝑖 – 4𝑖 = (− 8+ 2/3) + (( 1)/27−4)𝑖 = ((−24 + 2)/3) + ((1 − 4 ×27)/27)𝑖 = (−22)/3 + ((1 −108)/27)𝑖 = (−22)/3 + (( −107)/27)𝑖 = (−22)/3 − ( 107)/27 𝑖
