Ex 12.1, 3 - A toy is in form of a cone of radius 3.5 cm - Ex 12.1

part 2 - Ex 12.1, 3 - Ex 12.1 - Serial order wise - Chapter 12 Class 10 Surface Areas and Volumes
part 3 - Ex 12.1, 3 - Ex 12.1 - Serial order wise - Chapter 12 Class 10 Surface Areas and Volumes
part 4 - Ex 12.1, 3 - Ex 12.1 - Serial order wise - Chapter 12 Class 10 Surface Areas and Volumes
part 5 - Ex 12.1, 3 - Ex 12.1 - Serial order wise - Chapter 12 Class 10 Surface Areas and Volumes

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Ex 12.1, 3 A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of same radius. The total height of the toy is 15.5 cm. Find the total surface area of the toy. Total surface area of toy = Curved Surface area of hemisphere + Curved Surface area of cone Curved Surface area of hemisphere Radius of hemisphere = Radius of cone = r = 3.5 cm Curved surface area of hemisphere = 2šœ‹š‘Ÿ2 = 2 Ɨ22/7Ɨ (3.5)2 = 2 Ɨ22/7Ɨ (3.5)2 = 2 Ɨ22/7Ɨ 3.5 Ɨ 3.5 = 2 Ɨ 22 Ɨ 0.5 Ɨ 3.5 = 77 cm2 Curved surface area of cone Curved surface area of cone = š…š’“š’ Radius of cone = r = 3.5 cm Height of cone = Total height of toy – radius of hemisphere = 15.5 – 3.5 = 12 cm Now, we find slant height (l) We know that l2 = h2 + r2 l2 = (12)2 + (3.5)2 l2 = (12)2 + (7/2)^2 l2 = 144 + 49/4 l2 = (144(4) + 49)/4 l2 = (576 + 49)/4 l2 = šŸ”šŸšŸ“/šŸ’ l = √(625/4) l = √(25^2/2^2 ) l = šŸšŸ“/šŸ l = 12.5 cm Curved surface area of cone = Ļ€rš‘™ = 22/7 Ɨ 3.5 Ɨ 12.5 = 22 Ɨ 0.5 Ɨ 12.5 = 137.5 cm2 Now, Total surface area of toy = Curved Surface Area of hemisphere + Curved Surface Area of cone = 77 + 137.5 = 214.5 cm2 Hence, total surface area of the toy is 214.5 cm2

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo