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Computer Science - Class 12
Chapter 2 - File Handling in Python

To open a file c:\scores.txt for reading, we use



The syntax to open a file in python is as follows:

file_object= open(file_name, access_mode) 


  • the file_name will be c:\\scores.txt
  • The file should be opened for reading ,  so access_mode is “r” .

Therefore, the correct answer will be

infile = open(“c:\\scores.txt”, “r”)


So, the correct answer is (b). 

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