Computer Science - Class 12
Chapter 2 - File Handling in Python

To open a file c:\scores.txt for reading, we use

 

Answer:

The syntax to open a file in python is as follows:

file_object= open(file_name, access_mode) 

Here, 

  • the file_name will be c:\\scores.txt
  • The file should be opened for reading ,  so access_mode is “r” .

Therefore, the correct answer will be

infile = open(“c:\\scores.txt”, “r”)

 

So, the correct answer is (b). 

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.