In the given figure, a circle is inscribed in the quadrilateral ABCD. Given AB = 6cm, BC = 7cm and CD = 4cm. Find AD.
We know that
Lengths of tangents drawn from external point are equal
Thus,
AP = AS
BP = BQ
CR = CQ
DR = DS
Adding (1) + (2) + (3) + (4)
AP + BP + CR + DR = AS + BQ + CQ + DS
(AP + BP) + (CR + DR )= (AS + DS ) + (BQ + CQ)
AB + CD = AD + BC
Putting AB = 6cm, BC = 7cm and CD = 4cm
6 + 4 = AD + 7
10 = AD + 7
10 − 7 = AD
AD = 3 cm
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.
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